Solution #73 - Jabez/Edited - 17/3/2025 #37
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JRS296
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Mar 17, 2025
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| What This Code Does: | ||
| * Find zeros in the matrix | ||
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| * If a cell is 0, mark its row and column to be zero later. | ||
| * Use the first row & column as markers | ||
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| * To track if first row and column have zeros we use firstrow and firstcol boolean variables | ||
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| * Instead of creating extra memory, the first row and column store which rows/columns should be zero. | ||
| * Set the marked cells to zero | ||
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| * Go through the matrix and make elements 0 based on the markers. | ||
| * Handle the first row and column separately | ||
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| If the first row/column originally had a 0, set the entire first row/column to 0. | ||
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| Imagine this matrix: | ||
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| 1 2 3 | ||
| 4 0 6 | ||
| 7 8 9 | ||
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| After running the code, it becomes: | ||
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| 1 0 3 | ||
| 0 0 0 | ||
| 7 0 9 | ||
| The 0 at (1,1) caused its entire row and column to be zero. |
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This doesn't seem too clear. Could you try doing something like this? https://github.com/Dijkstra-Edu/LeetCode-Solutions/pull/16/files
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Also use the template File for your explanation: https://github.com/Dijkstra-Edu/LeetCode-Solutions/blob/master/Explanation-Template.md
JRS296
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Mar 17, 2025
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Solution and explanation added