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| 1 | +// Time: O(n) ~ O(n^2), O(n) on average |
| 2 | +// Space: O(1) |
| 3 | + |
| 4 | +// Tri Partition (aka Dutch National Flag Problem) with virtual index solution |
| 5 | +class Solution { |
| 6 | +public: |
| 7 | + vector<int> rearrangeArray(vector<int>& nums) { |
| 8 | + int mid = (size(nums) - 1) / 2; |
| 9 | + nth_element(begin(nums), begin(nums) + mid, end(nums)); // O(n) ~ O(n^2) time |
| 10 | + reversedTriPartitionWithVI(nums, nums[mid]); // O(n) time, O(1) space |
| 11 | + return nums; |
| 12 | + } |
| 13 | + |
| 14 | +private: |
| 15 | + void reversedTriPartitionWithVI(vector<int>& nums, int val) { |
| 16 | + const int N = size(nums) / 2 * 2 + 1; |
| 17 | + #define Nums(i) nums[(1 + 2 * (i)) % N] |
| 18 | + for (int i = 0, j = 0, n = size(nums) - 1; j <= n;) { |
| 19 | + if (Nums(j) > val) { |
| 20 | + swap(Nums(i++), Nums(j++)); |
| 21 | + } else if (Nums(j) < val) { |
| 22 | + swap(Nums(j), Nums(n--)); |
| 23 | + } else { |
| 24 | + ++j; |
| 25 | + } |
| 26 | + } |
| 27 | + } |
| 28 | +}; |
| 29 | + |
| 30 | +// Time: O(nlogn) |
| 31 | +// Space: O(n) |
| 32 | +// Sorting and reorder solution |
| 33 | +class Solution2 { |
| 34 | +public: |
| 35 | + vector<int> rearrangeArray(vector<int>& nums) { |
| 36 | + int mid = (size(nums) - 1) / 2; |
| 37 | + sort(begin(nums), end(nums)); // O(nlogn) time |
| 38 | + vector<int> result(size(nums)); // O(n) space |
| 39 | + for (int i = 0, smallEnd = mid; i < size(nums); i += 2, --smallEnd) { |
| 40 | + result[i] = nums[smallEnd]; |
| 41 | + } |
| 42 | + for (int i = 1, largeEnd = size(nums) - 1; i < size(nums); i += 2, --largeEnd) { |
| 43 | + result[i] = nums[largeEnd]; |
| 44 | + } |
| 45 | + return result; |
| 46 | + } |
| 47 | +}; |
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