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Create number-of-rectangles-that-can-form-the-largest-square.cpp
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// Time: O(n)
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// Space: O(1)
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class Solution {
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public:
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int countGoodRectangles(vector<vector<int>>& rectangles) {
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int result = 0, mx = 0;
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for (const auto& rec : rectangles) {
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int side = min(rec[0], rec[1]);
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if (side > mx) {
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mx = side;
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result = 1;
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} else if (side == mx) {
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++result;
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}
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}
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return result;
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}
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};

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