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| 1 | +// Time: O(n) |
| 2 | +// Space: O(h) |
| 3 | + |
| 4 | +/** |
| 5 | + * Definition for a binary tree node. |
| 6 | + * struct TreeNode { |
| 7 | + * int val; |
| 8 | + * TreeNode *left; |
| 9 | + * TreeNode *right; |
| 10 | + * TreeNode(int x) : val(x), left(NULL), right(NULL) {} |
| 11 | + * }; |
| 12 | + */ |
| 13 | + |
| 14 | +// iterative stack solution |
| 15 | +class Solution { |
| 16 | +public: |
| 17 | + int maxAncestorDiff(TreeNode* root) { |
| 18 | + using NODE = tuple<TreeNode*, int, int>; |
| 19 | + int result = 0; |
| 20 | + vector<NODE> stack{{root, 0, numeric_limits<int>::max()}}; |
| 21 | + while (!stack.empty()) { |
| 22 | + TreeNode *node; int mx, mn; |
| 23 | + tie(node, mx, mn) = stack.back(); stack.pop_back(); |
| 24 | + if (!node) { |
| 25 | + continue; |
| 26 | + } |
| 27 | + result = max(result, max(mx - node->val, node->val - mn)); |
| 28 | + mx = max(mx, node->val); |
| 29 | + mn = min(mn, node->val); |
| 30 | + stack.emplace_back(node->left, mx, mn); |
| 31 | + stack.emplace_back(node->right, mx, mn); |
| 32 | + } |
| 33 | + return result; |
| 34 | + } |
| 35 | +}; |
| 36 | + |
| 37 | +// Time: O(n) |
| 38 | +// Space: O(h) |
| 39 | +// recursive solution |
| 40 | +class Solution2 { |
| 41 | +public: |
| 42 | + int maxAncestorDiff(TreeNode* root) { |
| 43 | + return maxAncestorDiffHelper(root, 0, numeric_limits<int>::max()); |
| 44 | + } |
| 45 | + |
| 46 | +private: |
| 47 | + int maxAncestorDiffHelper(TreeNode* node, int mx, int mn) { |
| 48 | + if (!node) { |
| 49 | + return 0; |
| 50 | + } |
| 51 | + int result = max(mx - node->val, node->val - mn); |
| 52 | + mx = max(mx, node->val); |
| 53 | + mn = min(mn, node->val); |
| 54 | + result = max(result, maxAncestorDiffHelper(node->left, mx, mn)); |
| 55 | + result = max(result, maxAncestorDiffHelper(node->right, mx, mn)); |
| 56 | + return result; |
| 57 | + } |
| 58 | +}; |
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