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Create reverse-subarray-to-maximize-array-value.cpp
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// Time: O(n)
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// Space: O(1)
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class Solution {
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public:
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int maxValueAfterReverse(vector<int>& nums) {
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int result = 0, add = 0;
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int max_pair = numeric_limits<int>::min(), min_pair = numeric_limits<int>::max();
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for (int i = 1; i < nums.size(); ++i) {
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result += abs(nums[i-1] - nums[i]);
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add = max({add,
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abs(nums[0] - nums[i]) - abs(nums[i - 1] - nums[i]),
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abs(nums.back() - nums[i - 1]) - abs(nums[i - 1] - nums[i])});
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min_pair = min(min_pair, max(nums[i - 1], nums[i]));
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max_pair = max(max_pair, min(nums[i - 1], nums[i]));
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}
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return result + max(add, (max_pair - min_pair) * 2);
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}
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};

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