Fixing formatting with isomorphic question

Author: kennymkchan

README.md

@@ -276,50 +276,50 @@
   ```
   **View on Codepen:** http://codepen.io/kennymkchan/pen/xgNNNB?editors=0012
 
-  <a name="string--isIsomorphic"></a><a name="2.3"></a>
-  - **[2.3](#string--palindrome) Check if a given string is a isomorphic**
-
-    ```
-    For two strings to be isomorphic, all occurrences of a character in string A can be replaced with another character
-    to get string B. The order of the characters must be preserved. There must be one-to-one mapping for ever char of
-    string A to every char of string B.
-
-    `paper` and `title` would return true.
-    `egg` and `sad` would return false.
-    `dgg` and `add` would return true.
-    ```
-    ```javascript
-    isIsomorphic("egg", 'add'); // true
-    isIsomorphic("paper", 'title'); // true
-    isIsomorphic("kick", 'side'); // false
-
-    function isIsomorphic(firstString, secondString) {
-
-      // Check if the same lenght. If not, they cannot be isomorphic
-      if (firstString.length !== secondString.length) return false
-
-      var letterMap = {};
-
-      for (var i = 0; i < firstString.length; i++) {
-        var letterA = firstString[i],
-            letterB = secondString[i];
-
-        // If the letter does not exist, create a map and map it to the value
-        // of the second letter
-        if (letterMap[letterA] === undefined) {
-          letterMap[letterA] = letterB;
-        } else if (letterMap[letterA] !== letterB) {
-          // Eles if letterA already exists in the map, but it does not map to
-          // letterB, that means that A is mapping to more than one letter.
-          return false;
-        }
+<a name="string--isIsomorphic"></a><a name="2.3"></a>
+- **[2.3](#string--palindrome) Check if a given string is a isomorphic**
+
+  ```
+  For two strings to be isomorphic, all occurrences of a character in string A can be replaced with another character
+  to get string B. The order of the characters must be preserved. There must be one-to-one mapping for ever char of
+  string A to every char of string B.
+
+  `paper` and `title` would return true.
+  `egg` and `sad` would return false.
+  `dgg` and `add` would return true.
+  ```
+  ```javascript
+  isIsomorphic("egg", 'add'); // true
+  isIsomorphic("paper", 'title'); // true
+  isIsomorphic("kick", 'side'); // false
+
+  function isIsomorphic(firstString, secondString) {
+
+    // Check if the same lenght. If not, they cannot be isomorphic
+    if (firstString.length !== secondString.length) return false
+
+    var letterMap = {};
+
+    for (var i = 0; i < firstString.length; i++) {
+      var letterA = firstString[i],
+          letterB = secondString[i];
+
+      // If the letter does not exist, create a map and map it to the value
+      // of the second letter
+      if (letterMap[letterA] === undefined) {
+        letterMap[letterA] = letterB;
+      } else if (letterMap[letterA] !== letterB) {
+        // Eles if letterA already exists in the map, but it does not map to
+        // letterB, that means that A is mapping to more than one letter.
+        return false;
       }
-      // If after iterating through and conditions are satisfied, return true.
-      // They are isomorphic
-      return true;
     }
-    ```
-    **View on Codepen:** http://codepen.io/kennymkchan/pen/mRZgaj?editors=0012
+    // If after iterating through and conditions are satisfied, return true.
+    // They are isomorphic
+    return true;
+  }
+  ```
+  **View on Codepen:** http://codepen.io/kennymkchan/pen/mRZgaj?editors=0012
 
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