= S
+ .chars()
+ .map(|c| c.to_digit(10).unwrap() as usize)
+ .collect();
+ let k = k as usize;
+ let mut ans = MIN;
+
+ for a in 0..5 {
+ for b in 0..5 {
+ if a == b {
+ continue;
+ }
+
+ let mut curA = 0;
+ let mut curB = 0;
+ let mut preA = 0;
+ let mut preB = 0;
+ let mut t = [[MAX; 2]; 2];
+ let mut l: isize = -1;
+
+ for (r, &x) in s.iter().enumerate() {
+ curA += (x == a) as i32;
+ curB += (x == b) as i32;
+
+ while (r as isize - l) as usize >= k && curB - preB >= 2 {
+ let i = (preA & 1) as usize;
+ let j = (preB & 1) as usize;
+ t[i][j] = min(t[i][j], preA - preB);
+ l += 1;
+ if l >= 0 {
+ preA += (s[l as usize] == a) as i32;
+ preB += (s[l as usize] == b) as i32;
+ }
+ }
+
+ let i = (curA & 1 ^ 1) as usize;
+ let j = (curB & 1) as usize;
+ if t[i][j] != MAX {
+ ans = max(ans, curA - curB - t[i][j]);
+ }
+ }
+ }
+ }
+
+ ans
+ }
+}
diff --git a/solution/3500-3599/3565.Sequential Grid Path Cover/README.md b/solution/3500-3599/3565.Sequential Grid Path Cover/README.md
index b222082e1362d..00e1d79864415 100644
--- a/solution/3500-3599/3565.Sequential Grid Path Cover/README.md
+++ b/solution/3500-3599/3565.Sequential Grid Path Cover/README.md
@@ -62,8 +62,8 @@ tags:
提示：
+-------------+---------+
@@ -25,11 +25,11 @@ tags:
| employee_id | int |
| name | varchar |
+-------------+---------+
-employee_id is the unique identifier for this table.
-Each row contains information about an employee.
+employee_id 是这张表的唯一主键。
+每一行包含一名员工的信息。
-Table: performance_reviews
+表：performance_reviews
+-------------+------+
@@ -40,30 +40,31 @@ Each row contains information about an employee.
| review_date | date |
| rating | int |
+-------------+------+
-review_id is the unique identifier for this table.
-Each row represents a performance review for an employee. The rating is on a scale of 1-5 where 5 is excellent and 1 is poor.
+review_id 是这张表的唯一主键。
+每一行表示一名员工的绩效评估。评分在 1-5 的范围内，5分代表优秀，1分代表较差。
-Write a solution to find employees who have consistently improved their performance over their last three reviews.
+编写一个解决方案，以找到在过去三次评估中持续提高绩效的员工。
- - An employee must have at least
3 review to be considered
- - The employee's last
3 reviews must show strictly increasing ratings (each review better than the previous)
- - Use the most recent
3 reviews based on review_date for each employee
- - Calculate the improvement score as the difference between the latest rating and the earliest rating among the last
3 reviews
+ - 员工 至少需要
3 次评估 才能被考虑
+ - 员工过去的
3 次评估，评分必须 严格递增（每次评价都比上一次好）
+ - 根据
review_date 为每位员工分析最近的 3 次评估
+ - 进步分数 为最后
3 次评估中最后一次评分与最早一次评分之间的差值
-Return the result table ordered by improvement score in descending order, then by name in ascending order.
+返回结果表以 进步分数 降序 排序，然后以 名字 升序 排序。
-The result format is in the following example.
+结果格式如下所示。
-Example:
+
+示例：
-
Input:
+
输入：
-
employees table:
+
employees 表：
+-------------+----------------+
@@ -77,7 +78,7 @@ Each row represents a performance review for an employee. The rating is on a sca
+-------------+----------------+
-
performance_reviews table:
+
performance_reviews 表：
+-----------+-------------+-------------+--------+
@@ -103,7 +104,7 @@ Each row represents a performance review for an employee. The rating is on a sca
+-----------+-------------+-------------+--------+
-
Output:
+
输出：
+-------------+----------------+-------------------+
@@ -115,44 +116,44 @@ Each row represents a performance review for an employee. The rating is on a sca
+-------------+----------------+-------------------+
-
Explanation:
+
解释：
- - Alice Johnson (employee_id = 1):
+
- Alice Johnson (employee_id = 1)：
- - Has 4 reviews with ratings: 2, 3, 4, 5
- - Last 3 reviews (by date): 2023-04-15 (3), 2023-07-15 (4), 2023-10-15 (5)
- - Ratings are strictly increasing: 3 → 4 → 5
- - Improvement score: 5 - 3 = 2
+ - 有 4 次评估，分数：2, 3, 4, 5
+ - 最后 3 次评估（按日期）：2023-04-15 (3), 2023-07-15 (4), 2023-10-15 (5)
+ - 评分严格递增：3 → 4 → 5
+ - 进步分数：5 - 3 = 2
- - Carol Davis (employee_id = 3):
+
- Carol Davis (employee_id = 3)：
- - Has 4 reviews with ratings: 1, 2, 3, 4
- - Last 3 reviews (by date): 2023-06-10 (2), 2023-09-10 (3), 2023-12-10 (4)
- - Ratings are strictly increasing: 2 → 3 → 4
- - Improvement score: 4 - 2 = 2
+ - 有 4 次评估，分数：1, 2, 3, 4
+ - 最后 3 次评估（按日期）：2023-06-10 (2)，2023-09-10 (3)，2023-12-10 (4)
+ - 评分严格递增：2 → 3 → 4
+ - 进步分数：4 - 2 = 2
- - Bob Smith (employee_id = 2):
+
- Bob Smith (employee_id = 2)：
- - Has 4 reviews with ratings: 3, 2, 4, 5
- - Last 3 reviews (by date): 2023-05-01 (2), 2023-08-01 (4), 2023-11-01 (5)
- - Ratings are strictly increasing: 2 → 4 → 5
- - Improvement score: 5 - 2 = 3
+ - 有 4 次评估，分数：3，2，4，5
+ - 最后 3 次评估（按日期）：2023-05-01 (2)，2023-08-01 (4)，2023-11-01 (5)
+ - 评分严格递增：2 → 4 → 5
+ - 进步分数：5 - 2 = 3
- - Employees not included:
+
- 未包含的员工：
- - David Wilson (employee_id = 4): Last 3 reviews are all 4 (no improvement)
- - Emma Brown (employee_id = 5): Only has 2 reviews (needs at least 3)
+ - David Wilson (employee_id = 4)：之前 3 次评估都是 4 分（没有进步）
+ - Emma Brown (employee_id = 5)：只有 2 次评估（需要至少 3 次）
-
The output table is ordered by improvement_score in descending order, then by name in ascending order.
+
输出表以 improvement_score 降序排序，然后以 name 升序排序。