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Commit 028632c

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Time: 48 ms (47.76%) | Memory: 17.5 MB (91.62%) - LeetSync
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def isBalanced(self, root: Optional[TreeNode]) -> bool:
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def dfs(root):
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if not root:
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return [True, 0]
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left, right = dfs(root.left), dfs(root.right)
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is_balanced = (left[0] and right[0] and
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abs(left[1]-right[1])<=1)
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return [is_balanced, 1+max(left[1],right[1])]
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return dfs(root)[0]
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