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Linked_List/061.Rotate-List/Readme.md
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1. 确定链表的总长度Len,注意如果Len==0时的处理(此时可以顺便记录末尾节点end)
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2. 确定实际需要旋转的次数 k=k%Len
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-3. 令p从头指针前进 Len-k+1 步,就到了断开链表的位置。
+3. 令p从头指针前进 Len-k-1 步,就到了断开链表的位置。
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4. 将p->next作为新的head,原本的end之后指向原本的head,再把p的next指向NULL,
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[Leetcode Link](https://leetcode.com/problems/rotate-list)
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