Update Readme.md

Author: wisdompeak

Template/Inverse_Element/Readme.md

@@ -1,4 +1,7 @@
-CF中经常会要求这样输出结果：```Let this probability be represented as an irreducible fraction x/y. You have to print x⋅y^−1 mod 998244353, where y^−1 is the inverse element of y modulo 998244353 (such integer that y⋅y−1 has remainder 1 modulo 998244353).```
+CF中经常会要求这样输出结果：
+```
+Let this probability be represented as an irreducible fraction x/y. You have to print x⋅y^−1 mod 998244353, where y^−1 is the inverse element of y modulo 998244353 (such integer that y⋅y−1 has remainder 1 modulo 998244353).
+```
 
 这里的inverse element并不是指的倒数，而是逆元。y的逆元写作y^-1，
 
@@ -28,8 +31,9 @@ a^-1 ≡ a ^ (M-2)  (mod M)
 ```cpp
 const ll N = 1e6+7, M = 998244353;
 ll inv[N];
-for(inv[1]=1,i=2;i<N;++i)
-    inv[i]=(M - M/i) * inv[M % i] % M
+int i;
+for(inv[1]=1, i=2; i<N; ++i)
+    inv[i] = (M - M/i) * inv[M % i] % M
 ```
 
 #### 逆元的一些性质