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| 1 | +using PII = pair<int,int>; |
| 2 | +class Solution { |
| 3 | +public: |
| 4 | + int findCrossingTime(int n, int k, vector<vector<int>>& time) |
| 5 | + { |
| 6 | + priority_queue<PII, vector<PII>, greater<>>leftArrive; |
| 7 | + priority_queue<PII, vector<PII>, greater<>>rightArrive; |
| 8 | + for (int i=0; i<k; i++) |
| 9 | + leftArrive.push({0, i}); |
| 10 | + |
| 11 | + int nextFree = 0; |
| 12 | + priority_queue<PII>leftWait; |
| 13 | + priority_queue<PII>rightWait; |
| 14 | + |
| 15 | + int ret = 0; |
| 16 | + int count = 0; |
| 17 | + int taken = 0; |
| 18 | + |
| 19 | + while (count < n) |
| 20 | + { |
| 21 | + while (!leftArrive.empty() && leftArrive.top().first <= nextFree) |
| 22 | + { |
| 23 | + auto [arriveTime, id] = leftArrive.top(); |
| 24 | + leftArrive.pop(); |
| 25 | + leftWait.push({time[id][0]+time[id][2], id}); |
| 26 | + } |
| 27 | + while (!rightArrive.empty() && rightArrive.top().first <= nextFree) |
| 28 | + { |
| 29 | + auto [arriveTime, id] = rightArrive.top(); |
| 30 | + rightArrive.pop(); |
| 31 | + rightWait.push({time[id][0]+time[id][2], id}); |
| 32 | + } |
| 33 | + |
| 34 | + if (leftWait.empty() && rightWait.empty()) |
| 35 | + { |
| 36 | + int t1 = leftArrive.empty() ? INT_MAX : leftArrive.top().first; |
| 37 | + int t2 = rightArrive.empty() ? INT_MAX : rightArrive.top().first; |
| 38 | + nextFree = min(t1, t2); |
| 39 | + continue; |
| 40 | + } |
| 41 | + |
| 42 | + if (!rightWait.empty()) // R -> L |
| 43 | + { |
| 44 | + auto [_, id] = rightWait.top(); |
| 45 | + rightWait.pop(); |
| 46 | + nextFree += time[id][2]; |
| 47 | + leftArrive.push({nextFree+time[id][3], id}); |
| 48 | + |
| 49 | + count++; |
| 50 | + ret = max(ret, nextFree); |
| 51 | + } |
| 52 | + else if (!leftWait.empty()) // L -> R |
| 53 | + { |
| 54 | + if (taken == n) |
| 55 | + { |
| 56 | + while (!leftWait.empty()) |
| 57 | + leftWait.pop(); |
| 58 | + } else |
| 59 | + { |
| 60 | + auto [_, id] = leftWait.top(); |
| 61 | + leftWait.pop(); |
| 62 | + nextFree += time[id][0]; |
| 63 | + rightArrive.push({nextFree+time[id][1], id}); |
| 64 | + taken++; |
| 65 | + } |
| 66 | + } |
| 67 | + } |
| 68 | + |
| 69 | + return nextFree; |
| 70 | + } |
| 71 | +}; |
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